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Which of the following are the names of Python passing argument styles?
(Select two answers.)
How many hashes (+) does the code output to the screen?
The code snippet that you have sent is a loop that checks if a variable ''floor'' is less than or equal to 0 and prints a string accordingly. The code is as follows:
floor = 5 while floor > 0: print(''+'') floor = floor - 1
The code starts with assigning the value 5 to the variable ''floor''. Then, it enters a while loop that repeats as long as the condition ''floor > 0'' is true. Inside the loop, the code prints a ''+'' symbol to the screen, and then subtracts 1 from the value of ''floor''. The loop ends when ''floor'' becomes 0 or negative, and the code exits.
The code outputs five ''+'' symbols to the screen, one for each iteration of the loop. Therefore, the correct answer is C. five.
What is true about exceptions and debugging? (Select two answers.)
Exceptions and debugging are two important concepts in Python programming that are related to handling and preventing errors. Exceptions are errors that occur when the code cannot be executed properly, such as syntax errors, type errors, index errors, etc. Debugging is the process of finding and fixing errors in the code, using various tools and techniques. Some of the facts about exceptions and debugging are:
One try-except block may contain more than one except branch. A try-except block is a way of handling exceptions in Python, by using the keywords try and except. The try block contains the code that may raise an exception, and the except block contains the code that will execute if an exception occurs. You can have multiple except blocks for different types of exceptions, or for different actions to take. For example, you can write a try-except block like this:
try: # some code that may raise an exception except ValueError: # handle the ValueError exception except ZeroDivisionError: # handle the ZeroDivisionError exception except: # handle any other exception
The default (anonymous) except branch can be the last branch in the try-except block. The default except branch is the one that does not specify any exception type, and it will catch any exception that is not handled by the previous except branches. The default except branch can be the last branch in the try-except block, but it cannot be the first or the only branch. For example, you can write a try-except block like this:
try: # some code that may raise an exception except ValueError: # handle the ValueError exception except: # handle any other exception
This is a valid try-except block, and the default except branch will be the last branch. However, you cannot write a try-except block like this:
try: # some code that may raise an exception except: # handle any exception
Therefore, the correct answers are A. A tool that allows you to precisely trace program execution is called a debugger. and C. One try-except block may contain more than one except branch.
What is the expected result of running the following code?
The code snippet that you have sent is trying to use the index method to find the position of a value in a list. The code is as follows:
the_list = [1, 2, 3, 4, 5] print(the_list.index(6))
The code starts with creating a list called ''the_list'' that contains the numbers 1, 2, 3, 4, and 5. Then, it tries to print the result of calling the index method on the list with the argument 6. The index method is used to return the first occurrence of a value in a list. For example, the_list.index(1) returns 0, because 1 is the first value in the list.
However, the code has a problem. The problem is that the value 6 is not present in the list, so the index method cannot find it. This will cause a ValueError exception, which is an error that occurs when a function or operation receives an argument that has the right type but an inappropriate value. The code does not handle the exception, and therefore it will terminate with an error message.
The expected result of the code is an unhandled exception, because the code tries to find a value that does not exist in the list. Therefore, the correct answer is C. The code raises an unhandled exception.
What is the expected output of the following code?
The code snippet that you have sent is a conditional statement that checks if a variable ''counter'' is less than 0, greater than or equal to 42, or neither. The code is as follows:
if counter < 0: print('''') elif counter >= 42: print('''') else: print('''')
The code starts with checking if the value of ''counter'' is less than 0. If yes, it prints a single asterisk () to the screen and exits the statement. If no, it checks if the value of ''counter'' is greater than or equal to 42. If yes, it prints three asterisks () to the screen and exits the statement. If no, it prints two asterisks () to the screen and exits the statement.
The expected output of the code depends on the value of ''counter''. If the value of ''counter'' is 10, as shown in the image, the code will print two asterisks (**) to the screen, because 10 is neither less than 0 nor greater than or equal to 42. Therefore, the correct answer is C. * *