At ValidExamDumps, we consistently monitor updates to the Oracle 1Z0-071 exam questions by Oracle. Whenever our team identifies changes in the exam questions, objectives, focus areas or requirements, We immediately update our exam questions for both PDF and online practice exams. This commitment ensures our customers always have access to the most current and accurate questions. By preparing with these up to date and 100% exam domain coverage questions, our customers can successfully pass the Oracle Database SQL exam on their first attempt without needing additional materials or study guides.
Other certification materials providers often include outdated or removed questions by Oracle in their 1Z0-071 exam. These outdated questions lead to customers failing their Oracle Database SQL exam. In contrast, we ensure our questions bank includes only precise and up-to-date questions. Our main priority is your success in the Oracle 1Z0-071 exam, not profiting from selling obsolete exam questions in PDF or Online Practice Test.
Examine the description of the CUSTONERS table
CUSTON is the PRIMARY KEY.
You must derermine if any customers'derails have entered more than once using a different
costno,by listing duplicate name
Which two methode can you use to get the requlred resuit?
To determine if customer details have been entered more than once using a different custno, the following methods can be used:
SUBQUERY: A subquery can be used to find duplicate names by grouping the names and having a count greater than one.
SELECT custname FROM customers GROUP BY custname HAVING COUNT(custname) > 1;
Self Join: A self join can compare rows within the same table to find duplicates in the custname column, excluding matches with the same custno.
SELECT c1.custname FROM customers c1 JOIN customers c2 ON c1.custname = c2.custname AND c1.custno != c2.custno;
These methods allow us to find duplicates in the custname column regardless of the custno. Options A, B, and E are not applicable methods for finding duplicates in this context.
Which two queries execute successfully?
A: This statement will not execute successfully because you cannot subtract a DAY interval from a DATE directly. SYSDATE needs to be cast to a TIMESTAMP first.
B: This statement is correct. It adds an interval of '1' DAY to the current TIMESTAMP.
C: This statement is correct. It subtracts an interval of '1' MINUTE from '1' DAY.
D: This statement will not execute successfully. In Oracle, you cannot add intervals of different date fields (DAY and MONTH) directly.
E: This statement has a syntax error with the quotes around INTERVAL and a misspelling, it should be 'INTERVAL'.
Oracle Database 12c SQL supports interval arithmetic as described in the SQL Language Reference documentation.
Examine the description of the PRODUCT_INFORMATION table:
In SQL, when you want to count occurrences of null values using the COUNT function, you must remember that COUNT ignores null values. So, if you want to count rows with null list_price, you have to replace nulls with some value that can be counted. This is what the NVL function does. It replaces a null value with a specified value, in this case, 0.
A, C, and D options attempt to count list_price directly where it is null, but this will always result in a count of zero because COUNT does not count nulls. Option B correctly uses the NVL function to convert null list_price values to 0, which can then be counted. The WHERE list_price IS NULL clause ensures that only rows with null list_price are considered.
The SQL documentation confirms that COUNT does not include nulls in its count and NVL is used to substitute a value for nulls in an expression. So option B will give us the correct count of rows with a null list_price.
Examine the description of the SALES table:
The SALES table has 5,000 rows.
Examine this statement:
CREATE TABLE sales1 (prod id, cust_id, quantity_sold, price)
AS
SELECT product_id, customer_id, quantity_sold, price
FROM sales
WHERE 1=1
Which two statements are true?
When creating a new table with a query, the statements that are true are:
A . SALES1 is created with 1 row. This is incorrect actually; the given query with WHERE 1=1 will retrieve all rows from the sales table, not just one row. Therefore, SALES1 will be created with the same number of rows as in the SALES table, assuming there are no WHERE clause conditions limiting the rows.
D . SALES1 has NOT NULL constraints on any selected columns which had those constraints in the SALES table. This is true. When a table is created using a CREATE TABLE AS SELECT statement, the NOT NULL constraints on the columns in the selected columns are preserved in the new table.
Options B and C are incorrect:
B is incorrect because the primary key and unique constraints are not carried over to the new table when using the CREATE TABLE AS SELECT syntax.
C is incorrect in the context of this scenario. However, if interpreted as a standalone statement (ignoring A), C would be the correct description of the outcome since WHERE 1=1 will not filter out any rows.
Examine the description of the CUSTOMERS table:
Which three statements will do an implicit conversion?
A: No implicit conversion is done here because TO_CHAR is an explicit conversion from a numeric to a string data type.
B: Implicit conversion happens here because the '0001' string will be automatically converted to a numeric data type to match the CUSTOMER_ID field.
C: No implicit conversion is needed because 0001 is already a numeric literal.
D: Implicit conversion occurs here because the string '01-JAN-19' will be converted to a date type to compare with INSERT_DATE.
E: No implicit conversion; DATE is explicitly specified using the DATE keyword.
F: Incorrect syntax, it has typographical errors and also TO_DATE is an explicit function, not an implicit conversion.
Reference for SQL functions, conversions, and the CROSS JOIN behavior can be found in the Oracle Database SQL Language Reference 12c documentation.
