Free C++ Institute CPP Exam Practice Questions & Explanations
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What will happen when you attempt to compile and run the code below, assuming that you enter the following sequence: one two three
#include
#include
using namespace std;
int main ()
{
string a;
cin.getline(a);
cout< return 0; } Program will output:
What happens when you attempt to compile and run the following code?
#include
#include
using namespace std;
int main() {
int t[] = { 1, 1, 2, 2, 3, 3, 4, 4, 5, 5 };
string s[] = { "one", "one", "two", "two", "three","three", "four", "four", "five", "five"};
map
for (int i = 0; i < 10; i++) {
m.push_back(pair
}
for (map
cout << i?>first << " ";
}
return 0;
}
Which changes, introduced independently, will allow the code to compile and display ''one'' ''eight''
''nine'' ''ten''? Choose all that apply
#include
#include
#include
using namespace std;
class A {
int a;
public:
A(int a):a(a){}
int getA() const { return a;}
/* Insert Code Here 1 */
};
/* Insert Code Here 2 */
int main(){
int t[] ={ 3, 4, 2, 1, 6, 5, 7, 9, 8, 10 };
string s[] = {"three", "four", "two", "one", "six","five", "seven", "nine","eight","ten"};
map
for(int i=0; i<10; i++) {
m.insert(pair
}
m.erase(m.lower_bound(2),m.upper_bound(7));
map
for( ;i!= m.end(); i++) {
cout<
}
cout< return 0; }
What happens when you attempt to compile and run the following code?
#include
#include
#include
using namespace std;
template
ostream & out;
Out(ostream & o): out(o){}
void operator()(const T & val ) {
out< struct Sequence { int start; Sequence(int start):start(start){} int operator()() { return start++; } }; int main() { vector vector generate(v1.begin(), v1.end(), Sequence(1)); reverse_copy(v1.begin(),v1.end(), v2.rbegin()); sort(v2.begin(), v2.end(), less_equal for_each(v2.begin(), v2.end(), Out return 0; } Program outputs:
What happens when you attempt to compile and run the following code?
#include
#include
#include
#include
using namespace std;
template
ostream & out;
Out(ostream & o): out(o){}
void operator() (const T & val ) { out< int main() { int t1[]={1,2,3,4,5,6,7,8,9,10}; int t2[]={1,2,3,4,5,6,7,8,9,10}; vector vector vector transform(v1.begin(), v1.end(), v2.rbegin(), v3.begin(), minus for_each(v3.rbegin(), v3.rend(), Out return 0; } Program outputs: