What happens when you attempt to compile and run the following code?

#include

#include

#include

using namespace std;

int main(){

int t[] ={ 3, 4, 2, 1, 6, 5, 7, 9, 8, 0 };

vectorv(t, t+10);

multiset s1(v.begin(),v.end());

s1.insert(v.begin(),v.end());

pair::iterator,multiset::iterator> range;

range = s1.equal_range(6);

while (range.first != range.second) {

cout<<*range.first<<" "; range.first++;

}

return 0;

}

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What happens when you attempt to compile and run the following code?

#include

#include

#include

using namespace std;

templatestruct Out {

ostream & out;

Out(ostream & o): out(o){}

void operator()(const T & val ) {

out<

}

};

struct Sequence {

int start;

Sequence(int start):start(start){}

int operator()() {

return start++ ; }};

int main() {

vector v1(10);

generate(v1.rbegin(), v1.rend(), Sequence(1));

rotate(v1.begin(),v1.begin() + 1, v1.end() );

for_each(v1.begin(), v1.end(), Out(cout) );cout<

return 0;

}

Program outputs:

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What happens when you attempt to compile and run the following code?

#include

#include

#include

#include

#include

#include

using namespace std;

class B { int val;

public:

B(int v=0):val(v){}

int getV() const {return val;}

operator int() const { return val; };};

templatestruct Out {

ostream & out;

Out(ostream & o): out(o){}

void operator() (const T & val ) {out<

int main () {

int t[] = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10};

fstream f("test.out", ios::trunc|ios::out);

list l(t, t+10);

for_each(l.begin(), l.end(), Out(f));

f.close();

f.open("test.out");

for( ; f.good() ; ) {

B i;

f>>i;

cout<

}

f.close();

return 0;

}

Afile test.out will be opened writing

Bfile test.out will be truncated

Cfile test.out will be opened for reading

Dcompilation error

Eprogram will display sequence 1 2 3 4 5 6 7 8 9 10

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Correct Answer: D