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Which changes introduced independently will allow the code to compile and display 0 0 1 1 8 8 9 9
(choose all that apply)?
#include
#include
#include
using namespace std;
class A {
int a;
public:
A(int a):a(a){}
int getA() const { return a;}
/* Insert Code Here 1 */
};
/* Insert Code Here 2*/
int main(){
A t[] ={ 3, 4, 2, 1, 6, 5, 7, 9, 8, 0 };
sets(t, t+10);/* Replace Code Here 3 */
multiset s1(s.begin(),s.end());/* Replace Code Here 4 */
s1.insert(s.begin(),s.end());
s1.erase(s1.lower_bound(2),s1.upper_bound(7));
multiset::iterator i=s1.begin();/* Replace Code Here 5 */
for( ;i!= s1.end(); i++)
{
cout<getA()<<" ";
}
cout< return 0; }
What happens when you attempt to compile and run the following code?
#include
#include
#include
#include
using namespace std;
template
ostream & out;
Out(ostream & o): out(o){}
void operator() (const T & val ) { out< int main() { string t[]={"aaa","Aaa", "aAa","aaA","bbb","Bbb", "bBb", "bbB"}; vector sort(v1.begin(), v1.end()); for_each(v1.begin(), v1.end(), Out return 0; } Program outputs:
What happens when you attempt to compile and run the following code?
#include
#include
#include
using namespace std;
int main () {
int t[] = {1,2,3,4,5,1,2,3,4,5};
vector
vector
int m1[] = {1, 2, 3};
it = search (v.begin(), v.end(), m1, m1+3);
cout << "found at position: " << it?v.begin() << endl;
return 0;
}
Program outputs:
What happens when you attempt to compile and run the following code?
#include
#include
#include
#include
using namespace std;
void myfunction(int i) {
cout << " " << i;
}
int multiply (int a) {
return a*2;
}
int main() {
int t[] = { 10, 5, 9, 6, 2, 4, 7, 8, 3, 1 };
vector
set
transform(s1.begin(), s1.end(), v1.begin(), multiply);
transform(v1.begin(), v1.end(), s1.begin(), multiply);
for_each(s1.begin(), s1.end(), myfunction);
return 0;
}
Program outputs:
What happens when you attempt to compile and run the following code?
#include
#include
#include
#include
using namespace std;
class B { int val;
public:
B(int v=0):val(v){}
int getV() const {return val;}
operator int () const { return val;} };
template
ostream & out;
Out(ostream & o): out(o){}
void operator() (const T & val ) { out< struct Add : public binary_function { B operator() (const B & a, const B & b) const { return a+b; } }; int main() { B t[]={1,2,3,4,5,6,7,8,9,10}; vector v1(t, t+10); vector v2(10); transform(v1.begin(), v1.end(), v2.begin(), bind1st(Add(), 1)); for_each(v2.rbegin(), v2.rend(), Out(cout));cout< return 0; } Program outputs: